Chemistry is the science of change. But why do chemical reactions take place? Why do chemicals react with each other? The answer is in thermodynamics and kinetics, HPLC of Formula: C14H18I3N3O6, 76801-93-9, Name is 5-Amino-N1,N3-bis(2,3-dihydroxypropyl)-2,4,6-triiodoisophthalamide, SMILES is O=C(NCC(O)CO)C1=C(I)C(N)=C(I)C(C(NCC(O)CO)=O)=C1I, belongs to iodides-buliding-blocks compound. In a document, author is IGAU, A, introduce the new discover.
SYNTHESIS AND CHEMISTRY OF SECONDARY ALKYL IODIDE COMPLEXES OF THE FORMULA [(ETA-5-C5H5)RE(NO)(PPH3)(ICHRR’)]+BF4-
Reactions of deuterodichloromethane complex [(eta-5-C5H5)Re(NO)(PPh3) (ClCD2Cl)]+BF4- with (a) isopropyl iodide, (b) sec-butyl iodide, (c) cyclopentyl iodide, and (d) cyclohexyl iodide give secondary alkyl iodide complexes [(eta-5-C5H5)Re(NO) (PPh3)(ICHRR’)]+BF4- (3a-d) in good to high NMR yields, depending upon the quantity of alkyl iodide employed. These compounds are much less stable than analogous primary alkyl iodide complexes, but analytically pure 3d can be isolated from the reaction of (eta-5-C5H5)Re(NO)(PPh3)(CH3) and HBF4.OEt2 in neat cyclohexyl iodide (73%). Complex 3d decomposes in CD2Cl2 to give cyclohexyl fluoride, cyclohexene (74% total) and bridging halide complexes [(eta-5-C5H5)Re(NO)(PPh3)]2X+BF4- (X = I, 33%; Cl, 36%). The formation of cyclohexyl fluoride suggests BF4- participation in carbon-iodine bond cleavage. Reaction of 3d and PPh3 gives the substitution product [Ph3PC6H11]+BF4- (24%), cyclohexyl fluoride (24%), cyclohexene (30%) and (eta-5-C5H5)Re(NO)(PPh3)(I) (7, 95%). An analogous reaction of 3d and PPN+BR- gives cyclohexene (57%) and 7 (99%).
A reaction mechanism is the microscopic path by which reactants are transformed into products. Each step is an elementary reaction. In my other articles, you can also check out more blogs about 76801-93-9. HPLC of Formula: C14H18I3N3O6.